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A bag contains 5 white, 6 red and 4 green balls. One ball is drawn at random. WH
probability that the ball drawn is (i) green? (ii) white? (iii) non-red?
Answers
Answer:
Step-by-step explanation:
-First, find the total number of balls in the bag.
Total number of balls in the bag = 5+6+4
= 15
i) probability of getting a green ball.
-Now write the total number of green balls as numerator and total number of balls in the denominator.
like this,
Total number of green balls = 4
Probability of getting a green ball = 4/15
-See if you can simplify the fraction into it's simplest form.
4/15 can't be cancelled further . So,
the rational form can be written as 4:15.
ratio = 4:15
∴The probability of getting a green ball = 4:15
- Do the rest in the same manner.
ii)White ball
Total number of white balls =5
Probability of getting a white ball = 5/15
-This fraction can be simplyfied into
5/15 = 1/3
ratio= 1:3
∴Probability of getting a white ball =1:3
iii)Non- red ball
- Here, we have to add both the green and white balls, because they are the non- red balls.
Total number of non-red balls =5+4
=9
∴Probability of getting a non-red ball =9/15
- Don't forget to simplify!
9/15= 3/5
ratio = 3:5
∴Probability of getting a non-red ball =3:5
~~ done~~