dx d sin 2x (A) (sin 2x)–1/2 (B) cos 2x (sin 2x)–1/2 (C) 2 cos 2x (sin 2x)–1/2 (D) cos 2x (sin 2x)1/2
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Answer:
Correct option is
A
a=
4
5π
,b∈R
∫(sin2x−cos2x)dx=−
2
∫(
2
−1
sin2x+
2
1
cos2x)dx
=−
2
∫(sin2xsin
4
5π
−cos
4
5π
cos2x)dx
=−
2
cos(2x−
4
5π
)dx
=
2
2
sin(2x−
4
5π
)+b
=
2
1
sin(2x−5π/4 )+b
Comparing with 1/root2
sin(2x−a)+b
∴a= 5π /4, b ∈ R
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