Math, asked by NiharMadhavi9875, 1 year ago

∫dxx√1−x3=(a)13log|√1−x2+1√1−x2−1|(b)13log|√1−x2−1√1−x2+1|(c)23log|1√1−x3|(d)13log|1−x3|

Answers

Answered by keshawraj7410
1
question is not clearly written plz attach a photo
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