dy/dx-(1+cos2y)/(1-cos2y)=0
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use division rule...
{(1-cos2y) . dy/dx(1+cos2y) - dy/dx(1-cos2y) . (1+cos2y)} /( 1-cos2y)^2
so
(1-cos2y) . (-sin2y) . 2) -( sin2y . 2 )( 1+cos2y)
opening brackets
2sin2y cos2y - 2 sin2y -.2 sin2y - 2sin2y cos2y
after cancelling
-4sin2y/ (1-cos2y)^2
{(1-cos2y) . dy/dx(1+cos2y) - dy/dx(1-cos2y) . (1+cos2y)} /( 1-cos2y)^2
so
(1-cos2y) . (-sin2y) . 2) -( sin2y . 2 )( 1+cos2y)
opening brackets
2sin2y cos2y - 2 sin2y -.2 sin2y - 2sin2y cos2y
after cancelling
-4sin2y/ (1-cos2y)^2
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Using integration the differential equation will be
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