Question

dy/dx=1/(x-1)³(x-2)
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Answer 1

Step-by-step explanation:

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y=(x+2)(x−1)(x+3)(1)

Taking logarithms,

lny=ln(x+2)+ln(x−1)+ln(x+3)

Differentiating w.r.t x ,

1y\dy\dx=1x+2+1x−1+1x+3

\dy\dx=y(1x+2+1x−1+1x+3)

From (1):

\dy\dx=(x−1)(x+3)+(x+2)(x+3)+(x+2)(x−1)

\dy\dx=(x−1)(x+3)+(x+2)(x+3+x−1)

\dy\dx=(x2+2x−3)+(2x2+6x+4)

\dy\dx=3x2+8x+1

Answer 2

Step-by-step explanation:

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