Question

dy/dx=(1+x^2)/y+siny

solve​

Answer 1

Answer:

Step-by-step explanation:

$\frac{dy}{dx}=\frac{1+x^2}{y+siny}$

$\int\limits {y+siny} \, dy =\int\limits{1+x^2} \, dx$

$\frac{y^{2} }{2}-cosy=x+\frac{x^3}{3}+c$