Question

dy/dx=✓1-y²/✓1-x² please get the answer​

Answer 1

dy/dx = √1-y^2/ √1- x^2

dy/√1- y^2 = dx/√1- x^2

sin^-1 y = sin^-1 x + c

sin^-1 y - sin^-1x = c

sin^-1 (y ( √1- x^2 - x√1- y^2) = sin^-1c

y√1- x^2 - x√1- y^2 = c