dy/dx +(3/x)y = 6x^2
Solved by linear differential equation
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Hope this helps you
Step-by-step explanation:
This is already a linear equation, and doesn't need to be transformed into a linear equation like a Bernoulli's equation. Still if you you want to do that, the power of y in the RHS is 0, and hence the required substitution for the unknown function would be u=y^(1–0) = y, and so there will not be any change.
The integrating factor =e^{Int[(3/x)dx] = x^3, and the general solution is y(x^3)=Int[(x^3)6x^2.dx] +c or y(x^3)=(x^6)+c or y = (c/x^3)+x^3.
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