Question

dy dx (b) Find , if y= 1÷√x+1 -√x-1​

Answer 1

Answer:

-1/ 2✓x - 1 / 2✓x( ✓x +1 )^2

Step-by-step explanation:

y = 1 / ( ✓x + 1 ) - ✓x-1

y' = -( 1/2✓x) / ( ✓x +1 )^2 - 1/2✓x

y' =( -1/2✓x - ✓x/2 - 1/2✓x - 1)/( ✓x +1 )^2

y' = ( -1/✓x - ✓x/2 - 1) /( ✓x +1 )^2

y' = - ( x + 2 + 2✓x)/2✓x( ✓x +1 )^2

y' = { - ( ✓x +1 )^2 - 1 }/2✓x( ✓x +1 )^2

y' = -1/ 2✓x - 1 / 2✓x( ✓x +1 )^2