dy/dx = cos2 theta+costheta/cos2theta-sintheta
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Answer:
Given x=cosθ−cos2θ …………..(1)
y=sinθ−sin2θ …………(2)
Differentiating equation (1) & (2) w.r.t. θ.
dθ
dx
=−sinθ+2sin2θ
dθ
dy
=cosθ−2cos2θ
Now
dθ
dx
dθ
dy
=
2sin2θ−sinθ
cosθ−2cos2θ
.
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