Question

dy/dx
Find
if,
1) y = log(logx)​

Answer 1

Answer:

1/x.log(x)

Step-by-step explanation:

Given,

$y = log( log(x) )$

Differentiating both sides, we get,

$\frac{dy}{dx} = \frac{1}{ log(x) } \times \frac{d( log(x)) }{dx}$

$= \frac{dy}{dx} = \frac{1}{ log(x) } \times \frac{1}{x}$

as, we know that, differention of log(x) is 1/x

$= \frac{dy}{dx} = \frac{1}{x log(x) }$

Hope this will help you!