Dy/Dx if sin y+X = Log x
Answers
Answered by
0
Answer:
in(x+y)=log(x+y)
dx
d
[sin(x+y)]=
dx
d
[log(x+y)]
cos(x+y)
dx
d
(x+y)=
x+y
1
dx
d
(x+y)
cos(x+y)(1+
dx
dy
)=
x+y
1
(1+
dx
dy
)
cos(x+y)(1+
dx
dy
)−
x+y
1
(1+
dx
dy
)=0
(1+
dx
dy
)(cos(x+y)−
x+y
1
)=0
⇒ 1+
dx
dy
=0
∴
dx
dy
=−1
Answered by
0
Answer:
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