dy/dx=?
if y = logx/x^2
in the key the answer is (x^2-2y)/x^5
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Heya!!!
y = ( log x )/x²
dy/dx ={ (1/x) × x² - 2x log x }/x⁴
dy/dx = { x - 2x log x } / x⁴
dy/dx = { x² - 2x² log x } / x⁴ x¹
dy/dx = { x² - 2x⁴ y } / x⁴ x¹
Good Mornin! key is wrong.
True, I checked with my teacher. Thanks
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Thanks for the quick reply. I have reached the similar solution but it is not in the key/answer guide. I have mentioned above the recommended answer. So either the key is wrong or the question to reach particular solution. Thanks Again