Question

dy/dx of cosinverse (x^2-1)/(x^2+1)​

Answer 1

Answer:

I think the problem is √(cos^-1 t)

Take y= √(cos^-1 t)

Let y = √u where u = cos^-1 t

Then dy/dt = (dy/du)(du/dt)

dy/dt = (1/2√u) {-1/√(1-t^2)}

= (1/2√cos^-1 t) {-1/√(1-t^2)}

= -1/2{√cos^-1 t) {√(1-t^2)}