Question

dy/dx of (x log x-x)​

Answer 1

Answer:

Product rule: If y=uv then its differentiation is dydx=u×dvdx+v×dudx. Hence the second order derivative of xlogx is 1x.

Step-by-step explanation:

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Answer 2

Answer:

logx

Step-by-step explanation:

d/dx(xlogx) = x.d/dx(logx) + logx.d/dx(x)

= x.(1/x) + logx

= 1 + logx

Hence d/dx(xlogx-x) = (1 + logx) - (1)

= logx