Question

dy/dx= x^2+1/x-2
Find differences calculus ​

Answer 1

Step-by-step explanation:

We have,

$\frac{dy}{dx} = {x}^{2} + \frac{1}{x} - 2$

$= > dy = ( {x}^{2} + \frac{1}{x} - 2)dx$

Integrating both sides,

$= > \int \: dy = \int( {x}^{2} + \frac{1}{x} - 2)dx$

$= > \int \: dy = \int \: {x}^{2} dx + \int \frac{1}{x} dx - \int2dx$

$= > y = \frac{ {x}^{3} }{3} + ln(x) - 2x + c$