Question

dy/DX =x^3y^3-xv what is the general solution of D.E ​​

Answer 1

Answer:

Here, dy/dx + xy = x3y3 Therefore 1/y3(dy/dx) + x.1/y2 = x3 (1) Put 1/y2 = z. Then -2/y3(dy/dx) = dz/dx Therefore, Eq. (1) becomes - 1/2(dz/dx) + xz = x3 ⇒ dz/dx - 2xz = -2x3 It is in the linear form. So, the integrating factor e∫-2xdx = e-x^2. Multiplying by it,Read more on Sarthaks.com - https://www.sarthaks.com/563786/solve-the-differential-equation-dy-dx-x-3y-3-xy