Question

dy/dx+x.sin2y=x^3cos^2y

Answer 1

x.sin2y=x^3.cos^2y
differentiate w.r.t x
sin2y+x.cos2y.dy/dx=3x^2.cos^2y+x^3.2cosy.(-siny) dy/dx
sin2y-3x^2.cos^2y=dy/dx {-x^3.sin2y-xcos2y}
dy/dx={3x^2cos^2y-sin2y}/{x^3.sin2y+x.cos2y}