Math, asked by Anonymous, 10 months ago

dy/dx=(x+y+1)/x-y-1....this is the question of ordinary differnetial Eq. of first order​

Answers

Answered by chinu5552
1

Answer:

dy/dx=dy/dv × dv/dx

x+y+1/dv × dv/x-y-1

x/dv × dv/ x

1....

Here's ur answer friend

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