Question

dy/dx+xy = y²e^x²/2 logx
​

Answer 1

Answer:

GOOD MORNING MAM

Aaditya.N. Vankar

Class:7th B

Roll number:03

Present mam ‍♂️GOOD MORNING MAM

Aaditya.N. Vankar

Class:7th B

Roll number:03

Present mam ‍♂️

Answer 2

Answer:

e

−x

2

/2

=y(c−cosx)

Solve the following equation

dx

dy

+xy=−y

2

e

x2/2

sinx

Solution:- Let

y

2

1

dx

dy

+

y

1

x=−e

x2/2

sinx

⇒

dx

−dt

+tx=−e

x

2/2sinx

⇒

dx

dt

−tx=e

x2/2

sinx

I.F.=e

−∫xdx

=e

−x2/2

t×e

−x2/2

=∫e

−x2/2

−e

x2/2

sinxdx

t×e

−x2/2

=−cosx+c

y

1

e

−x2/2

=−cosx+c

y

1

e

−x2/2

=−cosx+c

e

−x2/2

=y(c−cosx)