Math, asked by ernestosantiago, 1 month ago

dy/dx -y = e^x y^2
ecuacion diferencial
diferencial equation

Answers

Answered by Beshram
3

Answer:

=e

x−y

(e

x

−e

y

)

dx

dy

=

e

y

e

x

(e

x

−e

y

)

e

y

dx

dy

=e

2x

−e

x

e

y

e

y

dx

dy

+e

x

e

y

=e

2x

Put e

y

=v

e

y

dx

dy

=

dx

dv

e

y

dx

dv

+ve

x

=e

2x

which is a linear differential eqn with v as dependent variable.

Here, P=e

x

;Q=e

2x

Integrating factor $$I.F.=e^\int{e^x}dx =e^{e^x}$$

So, the solution of given differential eqn is

v.e

e

x

=∫e

e

x

e

2x

dx+C

Put e

x

=t in the above integral

Step-by-step explanation:

Hope it will Helps You ❤️✨❤️✨❤️✨

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