Question

dy/dx, y=x sin x find the value
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Answer 1

Step-by-step explanation:

Solution

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y=x

sinx

logy=sinxlogx

dx

d

(logy)=

dx

d

(sinxlogx)

y

1

dx

dy

=sinx×

dx

d

(logx)+logx

dx

d

(sinx)

y

1

dx

dy

=sinx×

x

1

+logxsinx

dx

dy

=y(

x

sinx

+logxsinx)

∴

dx

dy

=x

sinx

(

x

sinx

+logxsinx)

Answer 2

Step-by-step explanation:

d/dx(x sinx)

: (d/dx(x))(sinx) + (d/dx(sinx))x

: sinx + xcosx