Question

dy/dx=y(y-xlogy)/x(x y logx)​

Answer 1

Answer:

x

y

=y

x

logx

y

=logy

x

ylogx=xlogy

Differentiating

dx

dy

logx+

x

y

=logy+

y

x

dx

dy

dx

dy

(logx−

y

x

)=logy−

x

y

dx

dy

y

(ylogx−x)

=

x

xlogy−y

dx

dy

=

x(ylogx−x)

y(xlogy−y)

Hence proved.

Step-by-step explanation:

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