dy/dy ? x=sin t y=cos2t
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Step-by-step explanation:
dy/dy=1
but if you wanna find dy/dx then
x=sin(t)
differentiating x with respect to t
dx/dt=cos(t)
and,
y= cos(2t)
differentiating y with respect to t
dy/dt= -2sin(2t)
Now,
dy/dx=(dy/dt)/(dx/dt)
dy/dx= -2sin(2t)/cos(t)
Hope you may get
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