dy Find if y =u³+ 2u and u=x² + 5.
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Answer:
6x^5 + 60x^3 +154x
Explanation:
Hope you asked
Given that, y = u^3 + 2u and u = x^2 + 5
This is solved using the parametric form
= *
dy/du = 3u^2 + 2
du/dx = 2x
Therefore, dy/dx = (3u^2 + 2)*2x = 6u^2 + 4x
Substitute for u,
dy/du = 6(x^2 +5)x + 4x = 6x^5 + 60x^3 +154x
Hope this helps!
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