Question

dy
.If y = x5+7x3+2x2+6x-3 then
dx​

Answer 1

Answer:

given y = x^5+7x^3+2x^2+6x-3

dy/do = d/dx(x^5+7x^3+2x^2+6x-3)

d/dx(x^5)+d/dx(7x^3)+d/dx(2x^2)+d/dx(6x)+d/dx(-3)

dy/dx = 5x^4+7(3x^2)+2(2x)+6(1)+0

dy/dx = 5x^4+21x^2+4x+6