Math, asked by CPTanurag, 2 days ago

dy Ifx+8 xy +y = 64, then= dy/dx is

Answers

Answered by adidesle

0

Answer:

3x 2

+8[x

dxdy

+y]+3y 2

dxdy

=0

⇒8[x

dxdy

+y]+3y 2

dxdy

=−3x 2

⇒8x

dxdy

+8y+3y 2

dxdy

= −3x 2

⇒8x

dxdy

+3y 2

dxdy

= −3x 2 −8y

⇒(8x+3y 2 ) dxdy

= −3x 2 −8y

⇒ dxdy

= (8x+3y 2 )−(3x 2 +8y)

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