dy Integrating factor of the differential equation (1+x2) + 2xy = COS X is dx
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(dy/dx)(x2)+2xy=cos2(x) (dy/dx)+2y/x=cos2x I multiplied both sides by e2ln x+c, then rewrote the equation as (d/dx)(y∗e2ln x+c)=(cos2(x)/x2)∗(e2ln please mark me as brain
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