e (1) P В Ta R Q S a, - In the figure, ZPQR = ZPQS = 90°, ZPRQ ZQPS = B, then find (i) sin a (ii) cos B (iii) tan (90 - a) (iv) cos (90-B) (v) sin (90 - a) (vi) tan ß(ans with explanation)
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i am a army too please re take the image and then ask cause image is blurry
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