Math, asked by akshay4500, 1 year ago

e) (15 - 9x – 21y + 8yz – 4x²y + 7y2x) – (3x²y – 6yx + 4xy? – 8y + 5x – 11)​

Answers

Answered by charliejaguars2002
10

Answer:

\Large\boxed{16xy+8yz-7x^2y-13y+26-14x}

Step-by-step explanation:

Given:

15 - 9x – 21y + 8yz – 4x²y + 7y2x) – (3x²y – 6yx + 4xy? – 8y + 5x – 11)​

To solve this problem, first you have to use distributive property from left to right numbers.

Solutions:

First, you have to remove parenthesis.

\displaystyle 15-9x-21y+8yz-4x^2y+7y*2x-(3x^2y-6yx+4xy-8y+5x-11)

Solve.

Multiply the numbers from left to right.

\displaystyle 2*7=14

Rewrite the problem down.

\displaystyle 15-9x-21y+8yz-4x^2y+14xy-(3x^2y+4xy+5x-6xy-8y-11)

Then, you add the numbers from left to right.

Add similar elements to from left to right numbers.

\displaystyle -6+4=-2

\displaystyle 15-9x-21y+8yz-4x^2y+14xy-(3x^2y+5x-2xy-8y-11)

\displaystyle 15-9x-21y+8yz-4x^2y+14xy-(3x^2y-2xy-8y+5x-11)

Solve.

\displaystyle -(3x^2y-2xy-8y+5x-11)

Solve/simplify with parenthesis.

\displaystyle -(3x^2y)-(-2xy)-(-8y)-(5x)-(-11)

\displaystyle -3x^2y+2xy+8y-5x+11

Rewrite the problem down.

\displaystyle 15-9x-21y+8yz-4x^2y+14yx-3x^2y+2xy+8y-5x+11

Solve. (Simplify/refine.)

Combine like terms. (Group like terms and switch sides.)

\displaystyle 4x^2y-3x^2y+14xy+2xy+8yz-21y+8y-9x-5x+15+11

Add numbers from left to right.

\displaystyle -4x^2y-3x^2y=-7x^2y

\displaystyle -7x^2y+14xy+2xy+8yz-21y+8y-9x-5x+15+11

\displaystyle -9-5=-14

\displaystyle -7x^2y+14xy+2xy+8yz-21y+8y-14x+15+11

Add similar elements to numbers from left to right.

\displaystyle 14xy+2xy=16xy

\displaystyle -7x^2y+16xy+8yz-21y+8y-14x+15+11

\displaystyle -21y+8y=-13y

\displaystyle -7x^2y+16xy+8yz-13y-14x+15+11

Solve.

Add numbers from left to right.

\displaystyle 15+11=26

\Large\boxed{16xy+8yz-7x^2y-13y+26-14x}

As a result, the correct answer is 16xy+8yz-7x²y-13y+26-14x.

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