(e) 16 and 3
49. The most contributing tautomeric enol form of
MeCOCH, CÓ Et is :
[JEE (WB) 2012]
(a) H2C=C(OH)CH2 CO2Et
(b) MeC(OH)=CHCO2 Et
giasoron
i gauwollo
(c) MeCOCH=C(OH)OEt
(d) H2C=C(OH)CH=C(OH)Et
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Answer:
16 and 3
49. The most contributing tautomeric enol form of
MeCOCH, CÓ Et is :
[JEE (WB) 2012]
(a) H2C=C(OH)CH2 CO2Et
(b) MeC(OH)=CHCO2 Et
giasoron
i gauwollo
(c) MeCOCH=C(OH)OEt
(d) H2C=C(OH)CH=C(OH)Et
Unable to understand sorry
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