Physics, asked by sahasachin51, 9 months ago

E-2.
Two particles A and B are initially 40 m apart. A is behind B. Particle A
of 10m/s towards B. Particle B starts from rest moving away from /
2 m/s?. The minimum distance between the two is:
(1) 15 m
(2) 20 m
(3) 25 m​

Answers

Answered by swayambhuvmitra
0

Answer:

20 \div 2 -  <  \sqrt[x1y5yxx {2}^{2}  \times \frac{2.556}{?} ]{?}  \times \frac{?}{?}

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