Question

e^2loge (1+x²) find the value​

Answer 1

Given

Now for maximum and minimum f ' (x) = 0

either , or or

But we have to search the minima and maxima in the interval [1, e]

Now at

is min. when

Therefore min. value

Now at

this is also + ve

But this is not possible that function has two min. values for two diff. values of x.

Thus, the function f(x) has no point of maximum and minimum in the interval [1, e].