Question

e^(3-12u)=0.4u
find the value of u ​

Answer 1

Answer:

given

e^(3-12u)=0.4u

applying anti log on both sides

3-12u=log 0.4u

3-12u=log 0.4+log u

3+0.398=log u+12u

3.398= log u +12u