Math, asked by umarparvez82, 10 months ago

e 3. Factorise the following polynomials:
9(a - 2b)2 - 16(2a - 3b)2

Answers

Answered by mindfulmaisel

Factorizing the given polynomial, we get $\bold{-55 a^{2}-108 b^{2}+156 a b.}$

Explanation:

Given:

$9(a-2 b)^{2}-16(2 a-3 b)^{2}$

Solution:

By formula $(a-b)^{2}=a^{2}+b^{2}+2 a b$

Hence $(a-2 b)^{2}=a^{2}+4 b^{2}-4 a b$

$(2 a-3 b)^{2}=4 a^{2}+9 b^{2}-12 a b$

Substituting the terms in the given polynomial, we get

$\begin{array}{l}{9(a-2 b)^{2}-16(2 a-3 b)^{2}=9\left[a^{2}+4 b^{2}-4 a b\right]-16\left[4 a^{2}+9 b^{2}-12 a b\right]} \\ \\{\left.=9 a^{2}+36 b^{2}-36 a b\right]-\left[64 a^{2}+144 b^{2}-192 a b\right]} \\ \\{=-55 a^{2}-108 b^{2}+156 a b}\end{array}$

Learn more about polynomials

If f and g are two polynomials of degree 3 and 4 respectively then what is the degree of f-g

https://brainly.in/question/9217128

Find the zeros of the quadratic polynomials given below. Find the sum and product of the zeros and verify relationship to the coefficients of terms in the polynomial.

(i) p(x) = x² – x – 6 (ii) p(x) = x² – 4x + 3

(iii) p(x) = x² – 4 (iv) p(x) = x² + 2x + 1

https://brainly.in/question/4915127

Answered by Aɾꜱɦ

$<font color =“orange”>$

${ \huge \bf{ \mid{ \overline{ \underline{Answer}}} \mid}}$

$<body bgcolor= “purple” ><fontcolor=“white”>$

-55a^{2}-108b^{2}+156ab

#answerwithquality #bal

Previous Question

Next Question

e 3. Factorise the following polynomials: 9(a - 2b)2 - 16(2a - 3b)2​

Answers

Factorizing the given polynomial, we get

e 3. Factorise the following polynomials:
9(a - 2b)2 - 16(2a - 3b)2

Factorizing the given polynomial, we get $\bold{-55 a^{2}-108 b^{2}+156 a b.}$