e^3logx differentiation
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3 xSquare
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Answer:
Basic Formulas:
→ 3.log x = log x³
→ d ( eˣ ) / dx = eˣ
→ e^log x = x
According to the question we are required to find the derivative of:
- e^3.logx
Applying the basic formula (1) we get,
→ e^3.log x = e^log x³
Differentiating we get,
⇒ d ( e^log x³ ) / dx
Applying chain rule we get,
→ e^log x³. 1/x³. 3x²
Therefore the final derivative of the given question is:
→ (3e^log x³)/x .
Now in Maths we generally consider log and ln to be same. Therefore applying basic formula (3) we get,
→ 3 ( e^log x³ ) / x
→ 3 ( x³ ) / x
→ 3x²
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