Question

E 5 Use the information given in the adjoining figure, to prove : (i) A DBC = A EAC. (ii) DC = = EC. A + B C​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

In given figure,

AC=BC,

∠EAC=∠DBC

And, ∠BCE=∠ACD

From figure ∠ACE=∠DCE+∠ACD

And ∠BCD=∠DCE+∠BCE

But, given in figure ∠ACD=∠BCE=x

∴∠BCD=∠ACE

In ΔDBC and ΔEAC

∠BDC=∠ACE

BC=AC

∠DBC=∠EAC

(i) ∴ΔDBC≅ΔEAC ....SAA test

Then, DC=EC

Step-by-step explanation:

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