E
8 cm
2 cm
12 em
F
G
А
4 cm
B
find area of the following quadrilateral
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Explanation:
8th
Maths
Mensuration
Introduction to Mensuration
ABCD is a rectangle with AB...
MATHS
ABCDis a rectangle with AB=12 cm and BC=7 cm Point E is on AD with DE=2cm, Point P is on AB. How far to the right of point A should point P be placed so that the shaded area comprises exactly 40% of the area of the rectangle?
291896
A
8
B
8.4
C
8.2
D
8.6
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ANSWER
Area of the rectangle ABCD=12×7=84sqcm.
Let AP=x cm. So, PB=(12−x) cm.
Area of shaded region =0.4×84=33.6 sq cm.
Area of triangle EAP=0.5×5×x=2.5x sq cm
Area of triangle CPB=0.5×7×(12−x)=42−3.5x sq cm
Sum of the area of triangles EAP and CPB = area of shaded region
2.5x+42−3.5x=33.6
42−x=33.6 or x=8.4cm
Point P should at 8.4 cm from vertex A.
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