e:9 Write the expression for the magnetic field on the axis of a circular coil due to
flow of current in it.
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Answer:
The expression is, B=μ0IR22(R2+x2)3/2, where R is the radius of the loop, I is the current flowing through it and x is the distance from the loop. That is, B=μ0IR22(R2+02)3/2=μ0IR22(R2)3/2=μ0I2R. Hence, the magnetic field at the centre of the circular loop will be B=μ0I2R.
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Explanation:
The expression is, B=μ0IR22(R2+x2)3/2, where R is the radius of the loop, I is the current flowing through it and x is the distance from the loop. That is, B=μ0IR22(R2+02)3/2=μ0IR22(R2)3/2=μ0I2R. Hence, the magnetic field at the centre of the circular loop will be B=μ0I2R.
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