Question

E = A*4 = B/4 = C+4 = D-4. A+B+C+D = 100. Find E by using only D as value.

Answer 1

Answer:

"A, B, C and D with respect to E

So, A*4=E , thus A= E/4

B/4=E, thus B=4E

C+4=E, thus C=E-4

D-4=E, thus the answer for D=E+4

Now, we know that,

A+B+C+D=100

Therefore,

(E/4) + (4E) + (E-4) + (E+4) = 100

=> (E/4) + (4E) + (2E) = 100

=> (E/4) + (6E) =100

=> (25E/4) = 100

=> E= (100*4)/25

=> E=16

The value of E is 16

=> E= (100*4)/25

=> E=16"

Answer 2

Answer:

E = 8

Step-by-step explanation:

E = A*4

=> A = E/4

E = B/4

=> B = 4E

E = C+4

=> C = E-4

E = D-4

=> D = E+4

& A+B+C+D = 100

=> Putting these values of A, B, C, & D

WE GET

E/4 + 4E + (E-4) + (E+4) = 100

=> E/4 + 4E + E - 4 + E + 4 = 100

=> (E + 16E + 4E - 16 + 4E + 16)/4 = 100

=> E + 16E + 4E + 4E = 100 × 4

=> 25E = 400

OR

E = 400/25 = 8 (answer)