Question

E=a+b/t find the dimensions of a and b

Answer 1

Answer:

$a  =\left[\ ML^{2}T^{-2}  \right]$

$b =\left[\ ML^{2}T^{-1}  \right]$

Explanation:

Equally dimensions are added and suntract.

$a=mc^{2}$ and $\frac{b}{t} =mc^{2}$

$mc^{2} =\left[\ ML^{2}T^{-2}  \right]$

$a  =\left[\ ML^{2}T^{-2}  \right]$

b

$\frac{b}{t}  =\left[\ ML^{2}T^{-2}  \right]$

$b =\left[\ ML^{2}T^{-1}  \right]$