Question

e. A ball falls off a table and reaches
the ground in 1 s. Assuming g = 10
m/s^2, calculate its speed on reaching
the ground and the height of the
table.
​

Answer 1

Answer:

here's your solution

Sol: g = 10m/s² , time =1s , u = 0

By newton's first equation

v = u+at

v= 0 + (10×1)

v = 0 + 10

v = 10m/s

Now, By newton's second equation

s = ut + (½ at²)

s = (0×10) + (½ ×10×1)

s = 0 + (½ ×10)

s = 0 + 5

s = 5m

Ans. speed of ball = 10m/s . Height of table from ground = 5m

------- By Enrique

Answer 2

Answer:

10 m/s and 5 m

Explanation:

According to the given question,

u = initial velocity = 0 m/s

t = time = 1s

g = gravity acceleration = 10 m/s^2

v = final velocity and s = displacement

And we are asked to find speed on reaching the ground and height.

Here, displacement is equal to height of the table as it's linear motion without changing it's direction. And velocity is equal to speed as direction is not changing only magnitude is changing because of free fall.

We know,

• v = u+at

Putting the values we get,

• v = 0+10×1

• v = 10 m/s

Again,

• s = ut+1/2 at^2

• s = 0+1/2 × 10 × 1

• s = 5 m

Thus speed is 10 m/s and height is 5 m.