Math, asked by kailashbenpstel, 5 hours ago

e ABCD is a quadrilateral in which AB is parallel
to CD and AD = BC = 5cm. It A= 105,
find the value of B

Answers

Answered by abusince05
0

Answer:

Given:ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º

We need to find the value of ∠B

Solution:

From the properties of a parallelogram, we know that

Vertically opposite angles are equal.

Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º

∠A + ∠B= 180º

105 +∠B =180º

∠B=180º-105º

∠B=75º

Step-by-step explanation:

hohe this is helpful to you

Answered by noreenkhanirhafatima
0

Step-by-step explanation:

Given:ABCD is a quadrilateral in which AB parallel to CD and AD=BC=5 if ∠A=105º

We need to find the value of ∠B

Solution:

From the properties of a parallelogram, we know that

Vertically opposite angles are equal.

Hence ∠A and ∠B forms Co interior angles and the sum of Co interior angles is 180º

∠A + ∠B= 180º

105 +∠B =180º

∠B=180º-105º

∠B=75º

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