e) An electric pump is used to lift water to a height of 60 m in 2 minutes. If the mass of the water raised is 800kg, find the power of pump. (g = 9.8m/s2)
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Answered by
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Total work done is the sum of potential and kinetic energies,
i.e. W=mgh+21mv2
Thus,
P=tW=tmgh+21mv2
=60(800×10×10)+21×800×(20)2
=4000W.
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Answered by
0
Answer:
Total work done is the sum of potential and kinetic energies,
i.e. W=mgh+ 21
mv 2
Thus,
P= tW
=tmgh+ 21mv 2
=60(800×10×10)+ 21×800×(20) 2
=4000W.
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