Question

E and F are points on diagonal AC of a parallelogram​

Answer 1

Answer:

According to question diagonal AC of a parallelogram ABCD such that AE = CF.

AE=CF

OE=OF

OA=OC

OD=OB

OA=OC

AE=CF

OA-AE=OC-CF

OE=OF

Answer 2

Answer:

ABCD is a parallelogram and AE=CF

Join BD, meet AC at point O.

Since, diagonals of a parallelogram bisect each other.

∴ OA=OC

and OD=OB

Now, OA=OC

and AE=CF [ Given ]

⇒ OA−AE=OC−CF

⇒ OE=OF

Thus, BFDE is a quadrilateral whose diagonals bisect each other.

Hence, BFDE is a parallelogram