E and F are points on the sides of PQ and PR respectively of PQR. for each of the following cases state whether EF||QR
1. PQ =1.28cm,PR =2.56cmand PE=0.18cm and PF =0.36cm
2.PE= 4cm ,QE=4.5cm PF=8cm and RF=9cm
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Answer:
(1.) EQ = 1.28 - 0.18 = 1.10 cm
Now,
PE / EQ = 0.18/1.1
FR = 2.56- 0.36 = 2.20 cm
here also,
PF/ FR = 0.36/2.2 = 0.18/1.1
We can say that,
PE/EQ = PF / FR
Thus by converse of BPT,
EF // QR.
(2.) PE/EQ = 4/4.5
PF/FR = 8/9
Since, PE/EQ is not equal to PF/FR
Thus,
EF is not parallel to QR.
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