Question

E and F are points on the sides PQ and PR respectively of a APQR. State whether EF || QR:
(i) PE = 3.9 cm, FQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm
​

Answer 1

Answer:

The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.

It is given that PE=3.9 cm, EQ=3 cm, PF=3.6 cm and FR=2.4 cm.

Using the basic proportionality theorem, we have

EQ

PE

=

3

3.9

=1.3

FR

PF

=

2.4

3.6

=1.5

Since

EQ

PE



=

FR

PF

Hence, EF is not parallel to QR.

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