Question

E and F are respectively the mid-points of equal sides AB and AC of AABC
(See figure) Then
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Answer 1

Answer:

Given E and F are mid point of equal sides AB and AC of triangle ABC

In ΔABF and ΔACE

AB=AC (given )

∠A=∠A (common angle )

AF=AE (halves of equal sides)

∴ΔABF≅ΔACE (SAS rule)

∴BF=CF (CPCT)