E and F are respectively the mid - points of equal sides AB and AC of ∆ABC(See figure)Then_________(A) BF=AC. (B)BE=AF. (C) CE =AB. (D) BF=AC
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Given E and F are mid point of equal sides AB and AC of triangle ABC
In ΔABF and ΔACE
AB=AC (given )
∠A=∠A (common angle )
AF=AE (halves of equal sides)
∴ΔABF≅ΔACE (SAS rule)
∴BF=CF (CPCT)
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