E and F are respectively the mid points of equal sides AB and AC of triangle ABC show that BF=CF
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It think you made a typing mistake. It should be show that BF = CE
Step-by-step explanation:
If AB = AC
therefore , ang. ABC = ang. ACB
and BE = CF (because E &F are the midpoints of equal sides)
Now in ∆EBC & ∆FCB
BE = CF
ang. ABC = ang. ACB
BC = BC (common side )
therefore, by SAS
∆'s are congruent
so , BF = CE (by CPCT)
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